Given an array of integers.

	Return an array, where the first element is the 
	count of positives numbers and the second element 
	is sum of negative numbers. 0 is neither positive 
	nor negative.

	If the input is an empty array or is null, return 
	an empty array.

	Example
				

	For input [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, -11, -12, -13, -14, -15], 
	you should return [10, -65].	
				

Solution by -

	function countPositivesSumNegatives(input) {
		if(input == null || input.length < 1){
			return []
		}
		else{
		let countOfPostives = input.filter( x => x > 0)
		let sumOfNegatives = input.filter( x => x < 0).reduce((a,b) => a + b, 0)
		return [countOfPostives.length, sumOfNegatives];
		}
	}

	OR

	function countPositivesSumNegatives(input) {
		let arrayAnswer = input && input.length ? [input.filter(x => x > 0).length, input.filter( y => y < 0).reduce((item1, item2) => item1 + item2,0) ]: []
				return arrayAnswer;
		}
				

Try it yourself - CodeWars

	Given an array of integers.

	Return an array, where the first element is the 
	count of positives numbers and the second element 
	is sum of negative numbers. 0 is neither positive 
	nor negative.

	If the input is an empty array or is null, return 
	an empty array.

	Example
				

	For input [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, -11, -12, -13, -14, -15], 
	you should return [10, -65].	
				

Solution by -

	function countPositivesSumNegatives(input) {
		if(input == null || input.length < 1){
			return []
		}
		else{
		let countOfPostives = input.filter( x => x > 0)
		let sumOfNegatives = input.filter( x => x < 0).reduce((a,b) => a + b, 0)
		return [countOfPostives.length, sumOfNegatives];
		}
	}

	OR

	function countPositivesSumNegatives(input) {
		let arrayAnswer = input && input.length ? [input.filter(x => x > 0).length, input.filter( y => y < 0).reduce((item1, item2) => item1 + item2,0) ]: []
				return arrayAnswer;
		}
				

Try it yourself - CodeWars