Given a number n, return the number of positive odd numbers below n, EASY!

	Examples (Input -> Output)
				

	* 7  -> 3 (because odd numbers below 7 are [1, 3, 5])
	* 15 -> 7 (because odd numbers below 15 are [1, 3, 5, 7, 9, 11, 13])
				

Solution by -

	function oddCount(n){
		return Math.floor(n/2)
		}
				

Try it yourself - CodeWars

	Given a number n, return the number of positive odd numbers below n, EASY!

	Examples (Input -> Output)
				

	* 7  -> 3 (because odd numbers below 7 are [1, 3, 5])
	* 15 -> 7 (because odd numbers below 15 are [1, 3, 5, 7, 9, 11, 13])
				

Solution by -

	function oddCount(n){
		return Math.floor(n/2)
		}
				

Try it yourself - CodeWars